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18000*(1+(3/20))^x-1/(3/20)*(1+(3/20))^x=76000 la ecuación

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Solución numérica:

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Solución

Ha introducido [src]
                              x        
                x   (3/20 + 1)         
18000*(3/20 + 1)  - ----------- = 76000
                        3/20           
$$- \frac{\left(\frac{3}{20} + 1\right)^{x}}{\frac{3}{20}} + 18000 \left(\frac{3}{20} + 1\right)^{x} = 76000$$
Solución detallada
Tenemos la ecuación:
$$- \frac{\left(\frac{3}{20} + 1\right)^{x}}{\frac{3}{20}} + 18000 \left(\frac{3}{20} + 1\right)^{x} = 76000$$
o
$$\left(- \frac{\left(\frac{3}{20} + 1\right)^{x}}{\frac{3}{20}} + 18000 \left(\frac{3}{20} + 1\right)^{x}\right) - 76000 = 0$$
o
$$\frac{53980 \left(\frac{23}{20}\right)^{x}}{3} = 76000$$
o
$$\left(\frac{23}{20}\right)^{x} = \frac{11400}{2699}$$
- es la ecuación exponencial más simple
Sustituimos
$$v = \left(\frac{23}{20}\right)^{x}$$
obtendremos
$$v - \frac{11400}{2699} = 0$$
o
$$v - \frac{11400}{2699} = 0$$
Transportamos los términos libres (sin v)
del miembro izquierdo al derecho, obtenemos:
$$v = \frac{11400}{2699}$$
Obtenemos la respuesta: v = 11400/2699
hacemos cambio inverso
$$\left(\frac{23}{20}\right)^{x} = v$$
o
$$x = \frac{\log{\left(v \right)}}{\log{\left(\frac{23}{20} \right)}}$$
Entonces la respuesta definitiva es
$$x_{1} = \frac{\log{\left(\frac{11400}{2699} \right)}}{\log{\left(\frac{23}{20} \right)}} = \log{\left(\left(\frac{11400}{2699}\right)^{\frac{1}{\log{\left(\frac{23}{20} \right)}}} \right)}$$
Gráfica
Respuesta rápida [src]
         /          1   \
         |       -------|
         |          /20\|
         |       log|--||
         |          \23/|
         |/11400\       |
x1 = -log||-----|       |
         \\ 2699/       /
$$x_{1} = - \log{\left(\left(\frac{11400}{2699}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)}$$
        /          1   \
        |       -------|
        |          /20\|
        |       log|--||
        |          \23/|
        |/ 2699\       |
x2 = log||-----|       |
        \\11400/       /
$$x_{2} = \log{\left(\left(\frac{2699}{11400}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)}$$
x2 = log((2699/11400)^(1/log(20/23)))
Suma y producto de raíces [src]
suma
     /          1   \      /          1   \
     |       -------|      |       -------|
     |          /20\|      |          /20\|
     |       log|--||      |       log|--||
     |          \23/|      |          \23/|
     |/11400\       |      |/ 2699\       |
- log||-----|       | + log||-----|       |
     \\ 2699/       /      \\11400/       /
$$- \log{\left(\left(\frac{11400}{2699}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)} + \log{\left(\left(\frac{2699}{11400}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)}$$
=
     /          1   \      /          1   \
     |       -------|      |       -------|
     |          /20\|      |          /20\|
     |       log|--||      |       log|--||
     |          \23/|      |          \23/|
     |/11400\       |      |/ 2699\       |
- log||-----|       | + log||-----|       |
     \\ 2699/       /      \\11400/       /
$$- \log{\left(\left(\frac{11400}{2699}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)} + \log{\left(\left(\frac{2699}{11400}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)}$$
producto
    /          1   \    /          1   \
    |       -------|    |       -------|
    |          /20\|    |          /20\|
    |       log|--||    |       log|--||
    |          \23/|    |          \23/|
    |/11400\       |    |/ 2699\       |
-log||-----|       |*log||-----|       |
    \\ 2699/       /    \\11400/       /
$$- \log{\left(\left(\frac{11400}{2699}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)} \log{\left(\left(\frac{2699}{11400}\right)^{\frac{1}{\log{\left(\frac{20}{23} \right)}}} \right)}$$
=
   2            2             /     log(7284601)\
log (2699) + log (11400) - log\11400            /
-------------------------------------------------
         2          2          /  log(400)\      
      log (20) + log (23) - log\23        /      
$$\frac{- \log{\left(11400^{\log{\left(7284601 \right)}} \right)} + \log{\left(2699 \right)}^{2} + \log{\left(11400 \right)}^{2}}{- \log{\left(23^{\log{\left(400 \right)}} \right)} + \log{\left(20 \right)}^{2} + \log{\left(23 \right)}^{2}}$$
(log(2699)^2 + log(11400)^2 - log(11400^log(7284601)))/(log(20)^2 + log(23)^2 - log(23^log(400)))
Respuesta numérica [src]
x1 = 10.3084716545887
x1 = 10.3084716545887