(x^4+2)(2x-5)=0 la ecuación
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Solución
Suma y producto de raíces
[src]
3/4 3/4 3/4 3/4 3/4 3/4 3/4 3/4
5 2 I*2 2 I*2 2 I*2 2 I*2
- + - ---- - ------ + - ---- + ------ + ---- - ------ + ---- + ------
2 2 2 2 2 2 2 2 2
$$\left(\left(\frac{2^{\frac{3}{4}}}{2} - \frac{2^{\frac{3}{4}} i}{2}\right) + \left(\left(\frac{5}{2} + \left(- \frac{2^{\frac{3}{4}}}{2} - \frac{2^{\frac{3}{4}} i}{2}\right)\right) + \left(- \frac{2^{\frac{3}{4}}}{2} + \frac{2^{\frac{3}{4}} i}{2}\right)\right)\right) + \left(\frac{2^{\frac{3}{4}}}{2} + \frac{2^{\frac{3}{4}} i}{2}\right)$$
$$\frac{5}{2}$$
/ 3/4 3/4\
| 2 I*2 |
5*|- ---- - ------| / 3/4 3/4\ / 3/4 3/4\ / 3/4 3/4\
\ 2 2 / | 2 I*2 | |2 I*2 | |2 I*2 |
-------------------*|- ---- + ------|*|---- - ------|*|---- + ------|
2 \ 2 2 / \ 2 2 / \ 2 2 /
$$\frac{5 \left(- \frac{2^{\frac{3}{4}}}{2} - \frac{2^{\frac{3}{4}} i}{2}\right)}{2} \left(- \frac{2^{\frac{3}{4}}}{2} + \frac{2^{\frac{3}{4}} i}{2}\right) \left(\frac{2^{\frac{3}{4}}}{2} - \frac{2^{\frac{3}{4}} i}{2}\right) \left(\frac{2^{\frac{3}{4}}}{2} + \frac{2^{\frac{3}{4}} i}{2}\right)$$
$$5$$
$$x_{1} = \frac{5}{2}$$
3/4 3/4
2 I*2
x2 = - ---- - ------
2 2
$$x_{2} = - \frac{2^{\frac{3}{4}}}{2} - \frac{2^{\frac{3}{4}} i}{2}$$
3/4 3/4
2 I*2
x3 = - ---- + ------
2 2
$$x_{3} = - \frac{2^{\frac{3}{4}}}{2} + \frac{2^{\frac{3}{4}} i}{2}$$
3/4 3/4
2 I*2
x4 = ---- - ------
2 2
$$x_{4} = \frac{2^{\frac{3}{4}}}{2} - \frac{2^{\frac{3}{4}} i}{2}$$
3/4 3/4
2 I*2
x5 = ---- + ------
2 2
$$x_{5} = \frac{2^{\frac{3}{4}}}{2} + \frac{2^{\frac{3}{4}} i}{2}$$
x5 = 2^(3/4)/2 + 2^(3/4)*i/2
x1 = 0.840896415253715 + 0.840896415253715*i
x2 = -0.840896415253715 + 0.840896415253715*i
x3 = 0.840896415253715 - 0.840896415253715*i
x4 = -0.840896415253715 - 0.840896415253715*i