(3/2)*((x+3)^(1/2))+(a-4)=0 la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Suma y producto de raíces
[src]
2 2
4*im (a) 4*(-4 + re(a)) 8*I*(-4 + re(a))*im(a)
-3 - -------- + --------------- + ----------------------
9 9 9
$$\frac{4 \left(\operatorname{re}{\left(a\right)} - 4\right)^{2}}{9} + \frac{8 i \left(\operatorname{re}{\left(a\right)} - 4\right) \operatorname{im}{\left(a\right)}}{9} - \frac{4 \left(\operatorname{im}{\left(a\right)}\right)^{2}}{9} - 3$$
2 2
4*im (a) 4*(-4 + re(a)) 8*I*(-4 + re(a))*im(a)
-3 - -------- + --------------- + ----------------------
9 9 9
$$\frac{4 \left(\operatorname{re}{\left(a\right)} - 4\right)^{2}}{9} + \frac{8 i \left(\operatorname{re}{\left(a\right)} - 4\right) \operatorname{im}{\left(a\right)}}{9} - \frac{4 \left(\operatorname{im}{\left(a\right)}\right)^{2}}{9} - 3$$
2 2
4*im (a) 4*(-4 + re(a)) 8*I*(-4 + re(a))*im(a)
-3 - -------- + --------------- + ----------------------
9 9 9
$$\frac{4 \left(\operatorname{re}{\left(a\right)} - 4\right)^{2}}{9} + \frac{8 i \left(\operatorname{re}{\left(a\right)} - 4\right) \operatorname{im}{\left(a\right)}}{9} - \frac{4 \left(\operatorname{im}{\left(a\right)}\right)^{2}}{9} - 3$$
2 2
4*im (a) 4*(-4 + re(a)) 8*I*(-4 + re(a))*im(a)
-3 - -------- + --------------- + ----------------------
9 9 9
$$\frac{4 \left(\operatorname{re}{\left(a\right)} - 4\right)^{2}}{9} + \frac{8 i \left(\operatorname{re}{\left(a\right)} - 4\right) \operatorname{im}{\left(a\right)}}{9} - \frac{4 \left(\operatorname{im}{\left(a\right)}\right)^{2}}{9} - 3$$
-3 - 4*im(a)^2/9 + 4*(-4 + re(a))^2/9 + 8*i*(-4 + re(a))*im(a)/9
2 2
4*im (a) 4*(-4 + re(a)) 8*I*(-4 + re(a))*im(a)
x1 = -3 - -------- + --------------- + ----------------------
9 9 9
$$x_{1} = \frac{4 \left(\operatorname{re}{\left(a\right)} - 4\right)^{2}}{9} + \frac{8 i \left(\operatorname{re}{\left(a\right)} - 4\right) \operatorname{im}{\left(a\right)}}{9} - \frac{4 \left(\operatorname{im}{\left(a\right)}\right)^{2}}{9} - 3$$
x1 = 4*(re(a) - 4)^2/9 + 8*i*(re(a) - 4)*im(a)/9 - 4*im(a)^2/9 - 3