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sh(5x-6y-6z) la ecuación

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Solución numérica:

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Solución

Ha introducido [src] 
sinh(5*x - 6*y - 6*z) = 0
$$\sinh{\left(- 6 z + \left(5 x - 6 y\right) \right)} = 0$$
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Respuesta rápida [src] 
                    /   _______                   \      /|   _______                  _______    |\
                    |12/  10*x  /         ___\  -y|      ||12/  10*x   -y       ___ 12/  10*x   -y||
z1 = -log(2) + I*arg\\/  e     *\-1 + I*\/ 3 /*e  / + log\|\/  e     *e   - I*\/ 3 *\/  e     *e  |/
$$z_{1} = \log{\left(\left|{\sqrt[12]{e^{10 x}} e^{- y} - \sqrt{3} i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(\left(-1 + \sqrt{3} i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /   _______                  \      /|   _______                  _______    |\
                    |12/  10*x  /        ___\  -y|      ||12/  10*x   -y       ___ 12/  10*x   -y||
z2 = -log(2) + I*arg\\/  e     *\1 - I*\/ 3 /*e  / + log\|\/  e     *e   - I*\/ 3 *\/  e     *e  |/
$$z_{2} = \log{\left(\left|{\sqrt[12]{e^{10 x}} e^{- y} - \sqrt{3} i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(\left(1 - \sqrt{3} i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /    _______                  \      /|   _______                  _______    |\
                    | 12/  10*x  /        ___\  -y|      ||12/  10*x   -y       ___ 12/  10*x   -y||
z3 = -log(2) + I*arg\-\/  e     *\1 + I*\/ 3 /*e  / + log\|\/  e     *e   + I*\/ 3 *\/  e     *e  |/
$$z_{3} = \log{\left(\left|{\sqrt[12]{e^{10 x}} e^{- y} + \sqrt{3} i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(- \left(1 + \sqrt{3} i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /   _______                  \      /|   _______                  _______    |\
                    |12/  10*x  /        ___\  -y|      ||12/  10*x   -y       ___ 12/  10*x   -y||
z4 = -log(2) + I*arg\\/  e     *\1 + I*\/ 3 /*e  / + log\|\/  e     *e   + I*\/ 3 *\/  e     *e  |/
$$z_{4} = \log{\left(\left|{\sqrt[12]{e^{10 x}} e^{- y} + \sqrt{3} i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(\left(1 + \sqrt{3} i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /   _______                \      /|         _______            _______    |\
                    |12/  10*x  /      ___\  -y|      ||  ___ 12/  10*x   -y     12/  10*x   -y||
z5 = -log(2) + I*arg\\/  e     *\I - \/ 3 /*e  / + log\|\/ 3 *\/  e     *e   - I*\/  e     *e  |/
$$z_{5} = \log{\left(\left|{\sqrt{3} \sqrt[12]{e^{10 x}} e^{- y} - i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(\left(- \sqrt{3} + i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /   _______                \      /|         _______            _______    |\
                    |12/  10*x  /  ___    \  -y|      ||  ___ 12/  10*x   -y     12/  10*x   -y||
z6 = -log(2) + I*arg\\/  e     *\\/ 3  - I/*e  / + log\|\/ 3 *\/  e     *e   - I*\/  e     *e  |/
$$z_{6} = \log{\left(\left|{\sqrt{3} \sqrt[12]{e^{10 x}} e^{- y} - i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(\left(\sqrt{3} - i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /    _______                \      /|     _______                _______    |\
                    | 12/  10*x  /      ___\  -y|      ||  12/  10*x   -y     ___ 12/  10*x   -y||
z7 = -log(2) + I*arg\-\/  e     *\I + \/ 3 /*e  / + log\|I*\/  e     *e   + \/ 3 *\/  e     *e  |/
$$z_{7} = \log{\left(\left|{\sqrt{3} \sqrt[12]{e^{10 x}} e^{- y} + i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(- \left(\sqrt{3} + i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
                    /   _______                \      /|     _______                _______    |\
                    |12/  10*x  /      ___\  -y|      ||  12/  10*x   -y     ___ 12/  10*x   -y||
z8 = -log(2) + I*arg\\/  e     *\I + \/ 3 /*e  / + log\|I*\/  e     *e   + \/ 3 *\/  e     *e  |/
$$z_{8} = \log{\left(\left|{\sqrt{3} \sqrt[12]{e^{10 x}} e^{- y} + i \sqrt[12]{e^{10 x}} e^{- y}}\right| \right)} + i \arg{\left(\left(\sqrt{3} + i\right) \sqrt[12]{e^{10 x}} e^{- y} \right)} - \log{\left(2 \right)}$$ 
          /    _______    \      /|   _______|        \
          | 12/  10*x   -y|      ||12/  10*x |  -re(y)|
z9 = I*arg\-\/  e     *e  / + log\|\/  e     |*e      /
$$z_{9} = \log{\left(e^{- \operatorname{re}{\left(y\right)}} \left|{\sqrt[12]{e^{10 x}}}\right| \right)} + i \arg{\left(- \sqrt[12]{e^{10 x}} e^{- y} \right)}$$ 
           /   _______    \      /|   _______|        \
           |12/  10*x   -y|      ||12/  10*x |  -re(y)|
z10 = I*arg\\/  e     *e  / + log\|\/  e     |*e      /
$$z_{10} = \log{\left(e^{- \operatorname{re}{\left(y\right)}} \left|{\sqrt[12]{e^{10 x}}}\right| \right)} + i \arg{\left(\sqrt[12]{e^{10 x}} e^{- y} \right)}$$ 
           /      _______    \      /|   _______|        \
           |   12/  10*x   -y|      ||12/  10*x |  -re(y)|
z11 = I*arg\-I*\/  e     *e  / + log\|\/  e     |*e      /
$$z_{11} = \log{\left(e^{- \operatorname{re}{\left(y\right)}} \left|{\sqrt[12]{e^{10 x}}}\right| \right)} + i \arg{\left(- i \sqrt[12]{e^{10 x}} e^{- y} \right)}$$ 
           /     _______    \      /|   _______|        \
           |  12/  10*x   -y|      ||12/  10*x |  -re(y)|
z12 = I*arg\I*\/  e     *e  / + log\|\/  e     |*e      /
$$z_{12} = \log{\left(e^{- \operatorname{re}{\left(y\right)}} \left|{\sqrt[12]{e^{10 x}}}\right| \right)} + i \arg{\left(i \sqrt[12]{e^{10 x}} e^{- y} \right)}$$ 
z12 = log(exp(-re(y))*Abs(exp(10*x)^(1/12))) + i*arg(i*exp(10*x)^(1/12)*exp(-y))
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