3*9^x=81 la ecuación
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Solución
Solución detallada
Tenemos la ecuación:
3 ⋅ 9 x = 81 3 \cdot 9^{x} = 81 3 ⋅ 9 x = 81 o
3 ⋅ 9 x − 81 = 0 3 \cdot 9^{x} - 81 = 0 3 ⋅ 9 x − 81 = 0 o
3 ⋅ 9 x = 81 3 \cdot 9^{x} = 81 3 ⋅ 9 x = 81 o
9 x = 27 9^{x} = 27 9 x = 27 - es la ecuación exponencial más simple
Sustituimos
v = 9 x v = 9^{x} v = 9 x obtendremos
v − 27 = 0 v - 27 = 0 v − 27 = 0 o
v − 27 = 0 v - 27 = 0 v − 27 = 0 Transportamos los términos libres (sin v)
del miembro izquierdo al derecho, obtenemos:
v = 27 v = 27 v = 27 Obtenemos la respuesta: v = 27
hacemos cambio inverso
9 x = v 9^{x} = v 9 x = v o
x = log ( v ) log ( 9 ) x = \frac{\log{\left(v \right)}}{\log{\left(9 \right)}} x = log ( 9 ) log ( v ) Entonces la respuesta definitiva es
x 1 = log ( 27 ) log ( 9 ) = 3 2 x_{1} = \frac{\log{\left(27 \right)}}{\log{\left(9 \right)}} = \frac{3}{2} x 1 = log ( 9 ) log ( 27 ) = 2 3
Gráfica
-12.5 -10.0 -7.5 -5.0 -2.5 0.0 2.5 5.0 7.5 10.0 12.5 15.0 0 500000000000
x 1 = 3 2 x_{1} = \frac{3}{2} x 1 = 2 3
log(27) pi*I
x2 = -------- + ------
2*log(3) log(3)
x 2 = log ( 27 ) 2 log ( 3 ) + i π log ( 3 ) x_{2} = \frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}} x 2 = 2 log ( 3 ) log ( 27 ) + log ( 3 ) iπ
x2 = log(27)/(2*log(3)) + i*pi/log(3)
Suma y producto de raíces
[src]
3 log(27) pi*I
- + -------- + ------
2 2*log(3) log(3)
3 2 + ( log ( 27 ) 2 log ( 3 ) + i π log ( 3 ) ) \frac{3}{2} + \left(\frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}}\right) 2 3 + ( 2 log ( 3 ) log ( 27 ) + log ( 3 ) iπ )
3 log(27) pi*I
- + -------- + ------
2 2*log(3) log(3)
3 2 + log ( 27 ) 2 log ( 3 ) + i π log ( 3 ) \frac{3}{2} + \frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}} 2 3 + 2 log ( 3 ) log ( 27 ) + log ( 3 ) iπ
/log(27) pi*I \
3*|-------- + ------|
\2*log(3) log(3)/
---------------------
2
3 ( log ( 27 ) 2 log ( 3 ) + i π log ( 3 ) ) 2 \frac{3 \left(\frac{\log{\left(27 \right)}}{2 \log{\left(3 \right)}} + \frac{i \pi}{\log{\left(3 \right)}}\right)}{2} 2 3 ( 2 l o g ( 3 ) l o g ( 27 ) + l o g ( 3 ) iπ )
9 3*pi*I
- + --------
4 2*log(3)
9 4 + 3 i π 2 log ( 3 ) \frac{9}{4} + \frac{3 i \pi}{2 \log{\left(3 \right)}} 4 9 + 2 log ( 3 ) 3 iπ
x2 = 1.5 + 2.85960086738013*i
x2 = 1.5 + 2.85960086738013*i