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2^x=4x+4 la ecuación

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Solución numérica:

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Solución

Ha introducido [src]
 x          
2  = 4*x + 4
$$2^{x} = 4 x + 4$$
Gráfica
Respuesta rápida [src]
           /-log(2) \
          W|--------|
           \   8    /
x1 = -1 - -----------
             log(2)  
$$x_{1} = -1 - \frac{W\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}$$
           /-log(2)     \
          W|--------, -1|
           \   8        /
x2 = -1 - ---------------
               log(2)    
$$x_{2} = -1 - \frac{W_{-1}\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}$$
x2 = -1 - LambertW(-log(2/8, -1)/log(2))
Suma y producto de raíces [src]
suma
      /-log(2) \         /-log(2)     \
     W|--------|        W|--------, -1|
      \   8    /         \   8        /
-1 - ----------- + -1 - ---------------
        log(2)               log(2)    
$$\left(-1 - \frac{W\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}\right) + \left(-1 - \frac{W_{-1}\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}\right)$$
=
      /-log(2) \    /-log(2)     \
     W|--------|   W|--------, -1|
      \   8    /    \   8        /
-2 - ----------- - ---------------
        log(2)          log(2)    
$$-2 - \frac{W\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}} - \frac{W_{-1}\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}$$
producto
/      /-log(2) \\ /      /-log(2)     \\
|     W|--------|| |     W|--------, -1||
|      \   8    /| |      \   8        /|
|-1 - -----------|*|-1 - ---------------|
\        log(2)  / \          log(2)    /
$$\left(-1 - \frac{W\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}\right) \left(-1 - \frac{W_{-1}\left(- \frac{\log{\left(2 \right)}}{8}\right)}{\log{\left(2 \right)}}\right)$$
=
/ /-log(2) \         \ / /-log(2)     \         \
|W|--------| + log(2)|*|W|--------, -1| + log(2)|
\ \   8    /         / \ \   8        /         /
-------------------------------------------------
                        2                        
                     log (2)                     
$$\frac{\left(W\left(- \frac{\log{\left(2 \right)}}{8}\right) + \log{\left(2 \right)}\right) \left(W_{-1}\left(- \frac{\log{\left(2 \right)}}{8}\right) + \log{\left(2 \right)}\right)}{\log{\left(2 \right)}^{2}}$$
(LambertW(-log(2)/8) + log(2))*(LambertW(-log(2)/8, -1) + log(2))/log(2)^2
Respuesta numérica [src]
x1 = 4.44490755461021
x2 = -0.862500371220299
x2 = -0.862500371220299