(0,2)^x-2=5^x2 la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
Tenemos la ecuación:
−2+(51)x=5x2o
−5x2+(−2+(51)x)=0Sustituimos
v=(51)xobtendremos
−5x2+v−2=0o
−5x2+v−2=0hacemos cambio inverso
(51)x=vo
x=−log(5)log(v)Entonces la respuesta definitiva es
x1=log(51)log(log(5)log(5x2+21))=−log(5)log(log(5)log(5x2+21))
/ 1 \ / 1 \
log|---------| I*arg|-------|
|| x2|| | x2|
\|2 + 5 |/ \2 + 5 /
x1 = -------------- + --------------
log(5) log(5)
x1=log(5)log(∣5x2+2∣1)+log(5)iarg(5x2+21)
x1 = log(1/|5^x2 + 2|)/log(5) + i*arg(1/(5^x2 + 2))/log(5)
Suma y producto de raíces
[src]
/ 1 \ / 1 \
log|---------| I*arg|-------|
|| x2|| | x2|
\|2 + 5 |/ \2 + 5 /
-------------- + --------------
log(5) log(5)
log(5)log(∣5x2+2∣1)+log(5)iarg(5x2+21)
/ 1 \ / 1 \
log|---------| I*arg|-------|
|| x2|| | x2|
\|2 + 5 |/ \2 + 5 /
-------------- + --------------
log(5) log(5)
log(5)log(∣5x2+2∣1)+log(5)iarg(5x2+21)
/ 1 \ / 1 \
log|---------| I*arg|-------|
|| x2|| | x2|
\|2 + 5 |/ \2 + 5 /
-------------- + --------------
log(5) log(5)
log(5)log(∣5x2+2∣1)+log(5)iarg(5x2+21)
/ 1 \ / 1 \
I*arg|-------| + log|---------|
| x2| || x2||
\2 + 5 / \|2 + 5 |/
-------------------------------
log(5)
log(5)log(∣5x2+2∣1)+iarg(5x2+21)
(i*arg(1/(2 + 5^x2)) + log(1/|2 + 5^x2|))/log(5)