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Expresión ¬a(b+c)+(¬b*¬c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ((¬b)∧(¬c))∨((¬a)∧(b∨c))
    $$\left(\neg a \wedge \left(b \vee c\right)\right) \vee \left(\neg b \wedge \neg c\right)$$
    Solución detallada
    $$\left(\neg a \wedge \left(b \vee c\right)\right) \vee \left(\neg b \wedge \neg c\right) = \left(\neg b \wedge \neg c\right) \vee \neg a$$
    Simplificación [src]
    $$\left(\neg b \wedge \neg c\right) \vee \neg a$$
    (¬a)∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNDP [src]
    $$\left(\neg b \wedge \neg c\right) \vee \neg a$$
    (¬a)∨((¬b)∧(¬c))
    FND [src]
    Ya está reducido a FND
    $$\left(\neg b \wedge \neg c\right) \vee \neg a$$
    (¬a)∨((¬b)∧(¬c))
    FNCD [src]
    $$\left(\neg a \vee \neg b\right) \wedge \left(\neg a \vee \neg c\right)$$
    ((¬a)∨(¬b))∧((¬a)∨(¬c))
    FNC [src]
    $$\left(\neg a \vee \neg b\right) \wedge \left(\neg a \vee \neg c\right)$$
    ((¬a)∨(¬b))∧((¬a)∨(¬c))