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Expresión ¬(a∨b)∨¬(b∧c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬(b∧c))∨(¬(a∨b))
    ¬(bc)¬(ab)\neg \left(b \wedge c\right) \vee \neg \left(a \vee b\right)
    Solución detallada
    ¬(bc)=¬b¬c\neg \left(b \wedge c\right) = \neg b \vee \neg c
    ¬(ab)=¬a¬b\neg \left(a \vee b\right) = \neg a \wedge \neg b
    ¬(bc)¬(ab)=¬b¬c\neg \left(b \wedge c\right) \vee \neg \left(a \vee b\right) = \neg b \vee \neg c
    Simplificación [src]
    ¬b¬c\neg b \vee \neg c
    (¬b)∨(¬c)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    ¬b¬c\neg b \vee \neg c
    (¬b)∨(¬c)
    FNDP [src]
    ¬b¬c\neg b \vee \neg c
    (¬b)∨(¬c)
    FND [src]
    Ya está reducido a FND
    ¬b¬c\neg b \vee \neg c
    (¬b)∨(¬c)
    FNCD [src]
    ¬b¬c\neg b \vee \neg c
    (¬b)∨(¬c)