Sr Examen
Expresión A&(BVC)=(A&B)V(A&C)
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Solución
Ha introducido
[src]
(a∧(b∨c))⇔((a∧b)∨(a∧c))
$$\left(a \wedge \left(b \vee c\right)\right) ⇔ \left(\left(a \wedge b\right) \vee \left(a \wedge c\right)\right)$$
Solución detallada
$$\left(a \wedge b\right) \vee \left(a \wedge c\right) = a \wedge \left(b \vee c\right)$$
$$\left(a \wedge \left(b \vee c\right)\right) ⇔ \left(\left(a \wedge b\right) \vee \left(a \wedge c\right)\right) = 1$$
$$\left(a \wedge \left(b \vee c\right)\right) ⇔ \left(\left(a \wedge b\right) \vee \left(a \wedge c\right)\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+