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Expresión ¬a∨¬b∨c∧a∨c∧¬a∨b---a∧c∨b∧b∧¬b∨(a∨c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(b∨(¬a)∨(¬b)∨(a∧c)∨(c∧(¬a)))|(a∨c∨(b∧(¬b))∨(c∧(¬a)))
$$\left(b \vee \left(a \wedge c\right) \vee \left(c \wedge \neg a\right) \vee \neg a \vee \neg b\right) | \left(a \vee c \vee \left(b \wedge \neg b\right) \vee \left(c \wedge \neg a\right)\right)$$
Solución detallada
$$b \vee \left(a \wedge c\right) \vee \left(c \wedge \neg a\right) \vee \neg a \vee \neg b = 1$$
$$b \wedge \neg b = \text{False}$$
$$a \vee c \vee \left(b \wedge \neg b\right) \vee \left(c \wedge \neg a\right) = a \vee c$$
$$\left(b \vee \left(a \wedge c\right) \vee \left(c \wedge \neg a\right) \vee \neg a \vee \neg b\right) | \left(a \vee c \vee \left(b \wedge \neg b\right) \vee \left(c \wedge \neg a\right)\right) = \neg a \wedge \neg c$$
$$b \wedge \neg b = \text{False}$$
$$a \vee c \vee \left(b \wedge \neg b\right) \vee \left(c \wedge \neg a\right) = a \vee c$$
$$\left(b \vee \left(a \wedge c\right) \vee \left(c \wedge \neg a\right) \vee \neg a \vee \neg b\right) | \left(a \vee c \vee \left(b \wedge \neg b\right) \vee \left(c \wedge \neg a\right)\right) = \neg a \wedge \neg c$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+