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Expresión (Q∨(P∧R))⇔(¬Q∨(P∧R))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (q∨(p∧r))⇔((¬q)∨(p∧r))
    $$\left(q \vee \left(p \wedge r\right)\right) ⇔ \left(\left(p \wedge r\right) \vee \neg q\right)$$
    Solución detallada
    $$\left(q \vee \left(p \wedge r\right)\right) ⇔ \left(\left(p \wedge r\right) \vee \neg q\right) = p \wedge r$$
    Simplificación [src]
    $$p \wedge r$$
    p∧r
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$p \wedge r$$
    p∧r
    FND [src]
    Ya está reducido a FND
    $$p \wedge r$$
    p∧r
    FNDP [src]
    $$p \wedge r$$
    p∧r
    FNC [src]
    Ya está reducido a FNC
    $$p \wedge r$$
    p∧r