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Expresión bc∨¬b¬c

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    Solución

    Ha introducido [src]
    (b∧c)∨((¬b)∧(¬c))
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    Simplificación [src]
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (b∧c)∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+--------+
    | b | c | result |
    +===+===+========+
    | 0 | 0 | 1      |
    +---+---+--------+
    | 0 | 1 | 0      |
    +---+---+--------+
    | 1 | 0 | 0      |
    +---+---+--------+
    | 1 | 1 | 1      |
    +---+---+--------+
    FNDP [src]
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (b∧c)∨((¬b)∧(¬c))
    FNC [src]
    $$\left(b \vee \neg b\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right) \wedge \left(c \vee \neg c\right)$$
    (b∨(¬b))∧(b∨(¬c))∧(c∨(¬b))∧(c∨(¬c))
    FNCD [src]
    $$\left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
    (b∨(¬c))∧(c∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$\left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    (b∧c)∨((¬b)∧(¬c))