Sr Examen
Expresión ∼[∼(∼𝑝∧𝑞)→∼𝑞]→p
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
¬(((¬(¬(p∧q)))⇒(¬q))⇒p)
$$\left(\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q\right) \not\Rightarrow p$$
Solución detallada
$$\neg \left(p \wedge q\right) = \neg p \vee \neg q$$
$$\neg \left(\neg \left(p \wedge q\right)\right) = p \wedge q$$
$$\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q = \neg p \vee \neg q$$
$$\left(\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q\right) \Rightarrow p = p$$
$$\left(\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q\right) \not\Rightarrow p = \neg p$$
$$\neg \left(\neg \left(p \wedge q\right)\right) = p \wedge q$$
$$\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q = \neg p \vee \neg q$$
$$\left(\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q\right) \Rightarrow p = p$$
$$\left(\neg \left(\neg \left(p \wedge q\right)\right) \Rightarrow \neg q\right) \not\Rightarrow p = \neg p$$
Tabla de verdad
+---+---+--------+ | p | q | result | +===+===+========+ | 0 | 0 | 1 | +---+---+--------+ | 0 | 1 | 1 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 0 | +---+---+--------+