Sr Examen
Expresión ¬(a|b|c)&d|a&d|b
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Solución
Ha introducido
[src]
(d∧(¬(a|b|c)))|(a∧d)|b
$$\left(d \wedge \neg \left(a | b | c\right)\right) | \left(a \wedge d\right) | b$$
Вы использовали:
| - Не-и (штрих Шеффера).
Возможно вы имели ввиду символ ∨ - Дизъюнкция (ИЛИ)?
Посмотреть с символом ∨
Solución detallada
$$a | b | c = \neg a \vee \neg b \vee \neg c$$
$$\neg \left(a | b | c\right) = a \wedge b \wedge c$$
$$d \wedge \neg \left(a | b | c\right) = a \wedge b \wedge c \wedge d$$
$$\left(d \wedge \neg \left(a | b | c\right)\right) | \left(a \wedge d\right) | b = \neg a \vee \neg b \vee \neg c \vee \neg d$$
$$\neg \left(a | b | c\right) = a \wedge b \wedge c$$
$$d \wedge \neg \left(a | b | c\right) = a \wedge b \wedge c \wedge d$$
$$\left(d \wedge \neg \left(a | b | c\right)\right) | \left(a \wedge d\right) | b = \neg a \vee \neg b \vee \neg c \vee \neg d$$
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 1 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 0 | +---+---+---+---+--------+