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Lógica matemática/ AvB&!C→!B

Expresión AvB&!C→!B

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (a∨(b∧(¬c)))⇒(¬b)
    $$\left(a \vee \left(b \wedge \neg c\right)\right) \Rightarrow \neg b$$
    Solución detallada
    $$\left(a \vee \left(b \wedge \neg c\right)\right) \Rightarrow \neg b = \left(c \wedge \neg a\right) \vee \neg b$$
    Simplificación [src]
    $$\left(c \wedge \neg a\right) \vee \neg b$$ 
    (¬b)∨(c∧(¬a))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 0      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(c \wedge \neg a\right) \vee \neg b$$ 
    (¬b)∨(c∧(¬a))
    FNCD [src]
    $$\left(c \vee \neg b\right) \wedge \left(\neg a \vee \neg b\right)$$ 
    (c∨(¬b))∧((¬a)∨(¬b))
    FNC [src]
    $$\left(c \vee \neg b\right) \wedge \left(\neg a \vee \neg b\right)$$ 
    (c∨(¬b))∧((¬a)∨(¬b))
    FNDP [src]
    $$\left(c \wedge \neg a\right) \vee \neg b$$ 
    (¬b)∨(c∧(¬a))
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