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Solución
Ha introducido
[src]
(b∧(¬a))∨(a∧c∧(¬b))∨(b∧c∧(¬a))
$$\left(b \wedge \neg a\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right)$$
Solución detallada
$$\left(b \wedge \neg a\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right) = \left(a \vee b\right) \wedge \left(b \vee c\right) \wedge \left(\neg a \vee \neg b\right)$$
Simplificación
[src]
$$\left(a \vee b\right) \wedge \left(b \vee c\right) \wedge \left(\neg a \vee \neg b\right)$$
(a∨b)∧(b∨c)∧((¬a)∨(¬b))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNDP
[src]
$$\left(b \wedge \neg a\right) \vee \left(a \wedge c \wedge \neg b\right)$$
(b∧(¬a))∨(a∧c∧(¬b))
FNC
[src]
Ya está reducido a FNC
$$\left(a \vee b\right) \wedge \left(b \vee c\right) \wedge \left(\neg a \vee \neg b\right)$$
(a∨b)∧(b∨c)∧((¬a)∨(¬b))
FNCD
[src]
$$\left(a \vee b\right) \wedge \left(b \vee c\right) \wedge \left(\neg a \vee \neg b\right)$$
(a∨b)∧(b∨c)∧((¬a)∨(¬b))
FND
[src]
$$\left(b \wedge \neg a\right) \vee \left(b \wedge \neg b\right) \vee \left(a \wedge b \wedge \neg a\right) \vee \left(a \wedge b \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg a\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(b \wedge c \wedge \neg b\right)$$
(b∧(¬a))∨(b∧(¬b))∨(a∧b∧(¬a))∨(a∧b∧(¬b))∨(a∧c∧(¬a))∨(a∧c∧(¬b))∨(b∧c∧(¬a))∨(b∧c∧(¬b))