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Lógica matemática/ bdc+(!b)d(!c)

Expresión bdc+(!b)d(!c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (b∧c∧d)∨(d∧(¬b)∧(¬c))
    $$\left(b \wedge c \wedge d\right) \vee \left(d \wedge \neg b \wedge \neg c\right)$$
    Solución detallada
    $$\left(b \wedge c \wedge d\right) \vee \left(d \wedge \neg b \wedge \neg c\right) = d \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
    Simplificación [src]
    $$d \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$ 
    d∧(b∨(¬c))∧(c∨(¬b))
    Tabla de verdad 
    +---+---+---+--------+
| b | c | d | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$d \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$ 
    d∧(b∨(¬c))∧(c∨(¬b))
    FND [src]
    $$\left(b \wedge c \wedge d\right) \vee \left(b \wedge d \wedge \neg b\right) \vee \left(c \wedge d \wedge \neg c\right) \vee \left(d \wedge \neg b \wedge \neg c\right)$$ 
    (b∧c∧d)∨(b∧d∧(¬b))∨(c∧d∧(¬c))∨(d∧(¬b)∧(¬c))
    FNDP [src]
    $$\left(b \wedge c \wedge d\right) \vee \left(d \wedge \neg b \wedge \neg c\right)$$ 
    (b∧c∧d)∨(d∧(¬b)∧(¬c))
    FNCD [src]
    $$d \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$ 
    d∧(b∨(¬c))∧(c∨(¬b))
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