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Lógica matemática/ ¬AvA&B&C

Expresión ¬AvA&B&C

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    Solución

    Ha introducido [src] 
    (¬a)∨(a∧b∧c)
    $$\left(a \wedge b \wedge c\right) \vee \neg a$$
    Solución detallada
    $$\left(a \wedge b \wedge c\right) \vee \neg a = \left(b \wedge c\right) \vee \neg a$$
    Simplificación [src]
    $$\left(b \wedge c\right) \vee \neg a$$ 
    (¬a)∨(b∧c)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    $$\left(b \vee \neg a\right) \wedge \left(c \vee \neg a\right)$$ 
    (b∨(¬a))∧(c∨(¬a))
    FNDP [src]
    $$\left(b \wedge c\right) \vee \neg a$$ 
    (¬a)∨(b∧c)
    FNC [src]
    $$\left(b \vee \neg a\right) \wedge \left(c \vee \neg a\right)$$ 
    (b∨(¬a))∧(c∨(¬a))
    FND [src]
    Ya está reducido a FND
    $$\left(b \wedge c\right) \vee \neg a$$ 
    (¬a)∨(b∧c)
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