Sr Examen
Expresión ¬(x⇒y¬z)∨¬x∨y
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
y∨(¬x)∨(¬(x⇒(y∧(¬z))))
$$y \vee \neg x \vee x \not\Rightarrow \left(y \wedge \neg z\right)$$
Solución detallada
$$x \Rightarrow \left(y \wedge \neg z\right) = \left(y \wedge \neg z\right) \vee \neg x$$
$$x \not\Rightarrow \left(y \wedge \neg z\right) = x \wedge \left(z \vee \neg y\right)$$
$$y \vee \neg x \vee x \not\Rightarrow \left(y \wedge \neg z\right) = 1$$
$$x \not\Rightarrow \left(y \wedge \neg z\right) = x \wedge \left(z \vee \neg y\right)$$
$$y \vee \neg x \vee x \not\Rightarrow \left(y \wedge \neg z\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+