Sr Examen
Expresión ⇔¬(¬p∧(p∨q))∨q
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Solución
Ha introducido
[src]
¬(q∨(¬((¬p)∧(p∨q))))
$$\neg \left(q \vee \neg \left(\neg p \wedge \left(p \vee q\right)\right)\right)$$
Solución detallada
$$\neg p \wedge \left(p \vee q\right) = q \wedge \neg p$$
$$\neg \left(\neg p \wedge \left(p \vee q\right)\right) = p \vee \neg q$$
$$q \vee \neg \left(\neg p \wedge \left(p \vee q\right)\right) = 1$$
$$\neg \left(q \vee \neg \left(\neg p \wedge \left(p \vee q\right)\right)\right) = \text{False}$$
$$\neg \left(\neg p \wedge \left(p \vee q\right)\right) = p \vee \neg q$$
$$q \vee \neg \left(\neg p \wedge \left(p \vee q\right)\right) = 1$$
$$\neg \left(q \vee \neg \left(\neg p \wedge \left(p \vee q\right)\right)\right) = \text{False}$$
Tabla de verdad
+---+---+--------+ | p | q | result | +===+===+========+ | 0 | 0 | 0 | +---+---+--------+ | 0 | 1 | 0 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 0 | +---+---+--------+