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Lógica matemática/ Bv(C&¬B)v(C&¬A&B)

Expresión Bv(C&¬B)v(C&¬A&B)

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    Solución

    Ha introducido [src] 
    b∨(c∧(¬b))∨(b∧c∧(¬a))
    $$b \vee \left(c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right)$$
    Solución detallada
    $$b \vee \left(c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right) = b \vee c$$
    Simplificación [src]
    $$b \vee c$$ 
    b∨c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$b \vee c$$ 
    b∨c
    FNDP [src]
    $$b \vee c$$ 
    b∨c
    FNCD [src]
    $$b \vee c$$ 
    b∨c
    FND [src]
    Ya está reducido a FND
    $$b \vee c$$ 
    b∨c
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