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Expresión (a\b\c)v(c\b\a)va&b&c

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b∧c)∨(a|b|c)∨(c|b|a)
    $$\left(a \wedge b \wedge c\right) \vee \left(a | b | c\right) \vee \left(c | b | a\right)$$
    Solución detallada
    $$a | b | c = \neg a \vee \neg b \vee \neg c$$
    $$c | b | a = \neg a \vee \neg b \vee \neg c$$
    $$\left(a \wedge b \wedge c\right) \vee \left(a | b | c\right) \vee \left(c | b | a\right) = 1$$
    Simplificación [src]
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    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    1
    1
    FNCD [src]
    1
    1
    FNDP [src]
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1