Expresión a&-b&-сvc&-b&-ava&b&c
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge b \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right) = \left(a \vee c\right) \wedge \left(a \vee \neg b\right) \wedge \left(c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right)$$
$$\left(a \vee c\right) \wedge \left(a \vee \neg b\right) \wedge \left(c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right)$$
(a∨c)∧(a∨(¬b))∧(c∨(¬b))∧(b∨(¬a)∨(¬c))
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FNC
$$\left(a \vee c\right) \wedge \left(a \vee \neg b\right) \wedge \left(c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right)$$
(a∨c)∧(a∨(¬b))∧(c∨(¬b))∧(b∨(¬a)∨(¬c))
$$\left(a \wedge b \wedge c\right) \vee \left(a \wedge b \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg a\right) \vee \left(a \wedge c \wedge \neg c\right) \vee \left(a \wedge \neg a \wedge \neg b\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg b\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(c \wedge \neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg a \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg b \wedge \neg c\right)$$
(a∧b∧c)∨(a∧b∧(¬b))∨(a∧c∧(¬a))∨(a∧c∧(¬c))∨(b∧c∧(¬b))∨(a∧(¬a)∧(¬b))∨(a∧(¬b)∧(¬c))∨(c∧(¬a)∧(¬b))∨(c∧(¬b)∧(¬c))∨(a∧b∧c∧(¬b))∨(a∧c∧(¬a)∧(¬b))∨(a∧c∧(¬b)∧(¬c))
$$\left(a \wedge b \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right)$$
(a∧b∧c)∨(a∧(¬b)∧(¬c))∨(c∧(¬a)∧(¬b))
$$\left(a \vee c\right) \wedge \left(a \vee \neg b\right) \wedge \left(c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right)$$
(a∨c)∧(a∨(¬b))∧(c∨(¬b))∧(b∨(¬a)∨(¬c))