El profesor se sorprenderá mucho al ver tu solución correcta😉
(b∨(¬a))⇔((¬a)∨(a∧b))
+---+---+--------+ | a | b | result | +===+===+========+ | 0 | 0 | 1 | +---+---+--------+ | 0 | 1 | 1 | +---+---+--------+ | 1 | 0 | 1 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+