Sr Examen

Expresión A+BC+(!B!C)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨(b∧c)∨((¬b)∧(¬c))
    $$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    Simplificación [src]
    $$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    a∨(b∧c)∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    a∨(b∧c)∨((¬b)∧(¬c))
    FNC [src]
    $$\left(a \vee b \vee \neg b\right) \wedge \left(a \vee b \vee \neg c\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(a \vee c \vee \neg c\right)$$
    (a∨b∨(¬b))∧(a∨b∨(¬c))∧(a∨c∨(¬b))∧(a∨c∨(¬c))
    FNCD [src]
    $$\left(a \vee b \vee \neg c\right) \wedge \left(a \vee c \vee \neg b\right)$$
    (a∨b∨(¬c))∧(a∨c∨(¬b))
    FNDP [src]
    $$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
    a∨(b∧c)∨((¬b)∧(¬c))