Sr Examen

Expresión ¬(¬avb)vc

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    c∨(¬(b∨(¬a)))
    $$c \vee \neg \left(b \vee \neg a\right)$$
    Solución detallada
    $$\neg \left(b \vee \neg a\right) = a \wedge \neg b$$
    $$c \vee \neg \left(b \vee \neg a\right) = c \vee \left(a \wedge \neg b\right)$$
    Simplificación [src]
    $$c \vee \left(a \wedge \neg b\right)$$
    c∨(a∧(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(a \vee c\right) \wedge \left(c \vee \neg b\right)$$
    (a∨c)∧(c∨(¬b))
    FNCD [src]
    $$\left(a \vee c\right) \wedge \left(c \vee \neg b\right)$$
    (a∨c)∧(c∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$c \vee \left(a \wedge \neg b\right)$$
    c∨(a∧(¬b))
    FNDP [src]
    $$c \vee \left(a \wedge \neg b\right)$$
    c∨(a∧(¬b))