Expresión F=Av(B&C)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$f ⇔ \left(a \vee \left(b \wedge c\right)\right) = \left(a \wedge f\right) \vee \left(b \wedge c \wedge f\right) \vee \left(\neg a \wedge \neg b \wedge \neg f\right) \vee \left(\neg a \wedge \neg c \wedge \neg f\right)$$
$$\left(a \wedge f\right) \vee \left(b \wedge c \wedge f\right) \vee \left(\neg a \wedge \neg b \wedge \neg f\right) \vee \left(\neg a \wedge \neg c \wedge \neg f\right)$$
(a∧f)∨(b∧c∧f)∨((¬a)∧(¬b)∧(¬f))∨((¬a)∧(¬c)∧(¬f))
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | f | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
Ya está reducido a FND
$$\left(a \wedge f\right) \vee \left(b \wedge c \wedge f\right) \vee \left(\neg a \wedge \neg b \wedge \neg f\right) \vee \left(\neg a \wedge \neg c \wedge \neg f\right)$$
(a∧f)∨(b∧c∧f)∨((¬a)∧(¬b)∧(¬f))∨((¬a)∧(¬c)∧(¬f))
$$\left(f \vee \neg a\right) \wedge \left(a \vee b \vee \neg f\right) \wedge \left(a \vee c \vee \neg f\right) \wedge \left(f \vee \neg b \vee \neg c\right)$$
(f∨(¬a))∧(a∨b∨(¬f))∧(a∨c∨(¬f))∧(f∨(¬b)∨(¬c))
$$\left(a \wedge f\right) \vee \left(b \wedge c \wedge f\right) \vee \left(\neg a \wedge \neg b \wedge \neg f\right) \vee \left(\neg a \wedge \neg c \wedge \neg f\right)$$
(a∧f)∨(b∧c∧f)∨((¬a)∧(¬b)∧(¬f))∨((¬a)∧(¬c)∧(¬f))
$$\left(f \vee \neg a\right) \wedge \left(f \vee \neg f\right) \wedge \left(a \vee b \vee \neg a\right) \wedge \left(a \vee b \vee \neg f\right) \wedge \left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg f\right) \wedge \left(a \vee f \vee \neg a\right) \wedge \left(a \vee f \vee \neg f\right) \wedge \left(b \vee f \vee \neg a\right) \wedge \left(b \vee f \vee \neg f\right) \wedge \left(c \vee f \vee \neg a\right) \wedge \left(c \vee f \vee \neg f\right) \wedge \left(f \vee \neg a \vee \neg b\right) \wedge \left(f \vee \neg a \vee \neg c\right) \wedge \left(f \vee \neg a \vee \neg f\right) \wedge \left(f \vee \neg b \vee \neg c\right) \wedge \left(f \vee \neg b \vee \neg f\right) \wedge \left(f \vee \neg c \vee \neg f\right) \wedge \left(a \vee b \vee \neg a \vee \neg b\right) \wedge \left(a \vee b \vee \neg a \vee \neg c\right) \wedge \left(a \vee b \vee \neg a \vee \neg f\right) \wedge \left(a \vee b \vee \neg b \vee \neg c\right) \wedge \left(a \vee b \vee \neg b \vee \neg f\right) \wedge \left(a \vee b \vee \neg c \vee \neg f\right) \wedge \left(a \vee c \vee \neg a \vee \neg b\right) \wedge \left(a \vee c \vee \neg a \vee \neg c\right) \wedge \left(a \vee c \vee \neg a \vee \neg f\right) \wedge \left(a \vee c \vee \neg b \vee \neg c\right) \wedge \left(a \vee c \vee \neg b \vee \neg f\right) \wedge \left(a \vee c \vee \neg c \vee \neg f\right) \wedge \left(a \vee f \vee \neg a \vee \neg b\right) \wedge \left(a \vee f \vee \neg a \vee \neg c\right) \wedge \left(a \vee f \vee \neg a \vee \neg f\right) \wedge \left(a \vee f \vee \neg b \vee \neg c\right) \wedge \left(a \vee f \vee \neg b \vee \neg f\right) \wedge \left(a \vee f \vee \neg c \vee \neg f\right) \wedge \left(b \vee f \vee \neg a \vee \neg b\right) \wedge \left(b \vee f \vee \neg a \vee \neg c\right) \wedge \left(b \vee f \vee \neg a \vee \neg f\right) \wedge \left(b \vee f \vee \neg b \vee \neg c\right) \wedge \left(b \vee f \vee \neg b \vee \neg f\right) \wedge \left(b \vee f \vee \neg c \vee \neg f\right) \wedge \left(c \vee f \vee \neg a \vee \neg b\right) \wedge \left(c \vee f \vee \neg a \vee \neg c\right) \wedge \left(c \vee f \vee \neg a \vee \neg f\right) \wedge \left(c \vee f \vee \neg b \vee \neg c\right) \wedge \left(c \vee f \vee \neg b \vee \neg f\right) \wedge \left(c \vee f \vee \neg c \vee \neg f\right)$$
(f∨(¬a))∧(f∨(¬f))∧(a∨b∨(¬a))∧(a∨b∨(¬f))∧(a∨c∨(¬a))∧(a∨c∨(¬f))∧(a∨f∨(¬a))∧(a∨f∨(¬f))∧(b∨f∨(¬a))∧(b∨f∨(¬f))∧(c∨f∨(¬a))∧(c∨f∨(¬f))∧(f∨(¬a)∨(¬b))∧(f∨(¬a)∨(¬c))∧(f∨(¬a)∨(¬f))∧(f∨(¬b)∨(¬c))∧(f∨(¬b)∨(¬f))∧(f∨(¬c)∨(¬f))∧(a∨b∨(¬a)∨(¬b))∧(a∨b∨(¬a)∨(¬c))∧(a∨b∨(¬a)∨(¬f))∧(a∨b∨(¬b)∨(¬c))∧(a∨b∨(¬b)∨(¬f))∧(a∨b∨(¬c)∨(¬f))∧(a∨c∨(¬a)∨(¬b))∧(a∨c∨(¬a)∨(¬c))∧(a∨c∨(¬a)∨(¬f))∧(a∨c∨(¬b)∨(¬c))∧(a∨c∨(¬b)∨(¬f))∧(a∨c∨(¬c)∨(¬f))∧(a∨f∨(¬a)∨(¬b))∧(a∨f∨(¬a)∨(¬c))∧(a∨f∨(¬a)∨(¬f))∧(a∨f∨(¬b)∨(¬c))∧(a∨f∨(¬b)∨(¬f))∧(a∨f∨(¬c)∨(¬f))∧(b∨f∨(¬a)∨(¬b))∧(b∨f∨(¬a)∨(¬c))∧(b∨f∨(¬a)∨(¬f))∧(b∨f∨(¬b)∨(¬c))∧(b∨f∨(¬b)∨(¬f))∧(b∨f∨(¬c)∨(¬f))∧(c∨f∨(¬a)∨(¬b))∧(c∨f∨(¬a)∨(¬c))∧(c∨f∨(¬a)∨(¬f))∧(c∨f∨(¬b)∨(¬c))∧(c∨f∨(¬b)∨(¬f))∧(c∨f∨(¬c)∨(¬f))