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Lógica matemática/ с∧(¬a∧¬b)∧(cvb)vc

Expresión с∧(¬a∧¬b)∧(cvb)vc

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    c∨(c∧(¬a)∧(¬b)∧(b∨c))
    c∨(c∧¬a∧¬b∧(b∨c))c \vee \left(c \wedge \neg a \wedge \neg b \wedge \left(b \vee c\right)\right)
    Solución detallada
    c∧¬a∧¬b∧(b∨c)=c∧¬a∧¬bc \wedge \neg a \wedge \neg b \wedge \left(b \vee c\right) = c \wedge \neg a \wedge \neg b
    c∨(c∧¬a∧¬b∧(b∨c))=cc \vee \left(c \wedge \neg a \wedge \neg b \wedge \left(b \vee c\right)\right) = c
    Simplificación [src]
    cc 
    c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    cc 
    c
    FND [src]
    Ya está reducido a FND
    cc 
    c
    FNDP [src]
    cc 
    c
    FNC [src]
    Ya está reducido a FNC
    cc 
    c
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