Sr Examen
Expresión p^(qVr)=(p^q)V(p^r)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(p∧(q∨r))⇔((p∧q)∨(p∧r))
$$\left(p \wedge \left(q \vee r\right)\right) ⇔ \left(\left(p \wedge q\right) \vee \left(p \wedge r\right)\right)$$
Solución detallada
$$\left(p \wedge q\right) \vee \left(p \wedge r\right) = p \wedge \left(q \vee r\right)$$
$$\left(p \wedge \left(q \vee r\right)\right) ⇔ \left(\left(p \wedge q\right) \vee \left(p \wedge r\right)\right) = 1$$
$$\left(p \wedge \left(q \vee r\right)\right) ⇔ \left(\left(p \wedge q\right) \vee \left(p \wedge r\right)\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | p | q | r | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+