Sr Examen
Expresión (¬avb)&(¬bvc)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(b∨(¬a))∧(c∨(¬b))
$$\left(b \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
Solución detallada
$$\left(b \vee \neg a\right) \wedge \left(c \vee \neg b\right) = \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
Simplificación
[src]
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
(b∧c)∨((¬a)∧(¬b))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FND
[src]
Ya está reducido a FND
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
(b∧c)∨((¬a)∧(¬b))
FNC
[src]
$$\left(b \vee \neg a\right) \wedge \left(b \vee \neg b\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
(b∨(¬a))∧(b∨(¬b))∧(c∨(¬a))∧(c∨(¬b))