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Lógica matemática/ B&((¬a->b)&C)

Expresión B&((¬a->b)&C)

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    Solución

    Ha introducido [src] 
    b∧c∧((¬a)⇒b)
    $$b \wedge c \wedge \left(\neg a \Rightarrow b\right)$$
    Solución detallada
    $$\neg a \Rightarrow b = a \vee b$$
    $$b \wedge c \wedge \left(\neg a \Rightarrow b\right) = b \wedge c$$
    Simplificación [src]
    $$b \wedge c$$ 
    b∧c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$b \wedge c$$ 
    b∧c
    FNC [src]
    Ya está reducido a FNC
    $$b \wedge c$$ 
    b∧c
    FNCD [src]
    $$b \wedge c$$ 
    b∧c
    FNDP [src]
    $$b \wedge c$$ 
    b∧c
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