Sr Examen
Expresión с∧¬b∨d∧¬c∧¬b∧a
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(c∧(¬b))∨(a∧d∧(¬b)∧(¬c))
$$\left(c \wedge \neg b\right) \vee \left(a \wedge d \wedge \neg b \wedge \neg c\right)$$
Solución detallada
$$\left(c \wedge \neg b\right) \vee \left(a \wedge d \wedge \neg b \wedge \neg c\right) = \neg b \wedge \left(a \vee c\right) \wedge \left(c \vee d\right)$$
Simplificación
[src]
$$\neg b \wedge \left(a \vee c\right) \wedge \left(c \vee d\right)$$
(¬b)∧(a∨c)∧(c∨d)
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 0 | +---+---+---+---+--------+
FND
[src]
$$\left(c \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(a \wedge d \wedge \neg b\right) \vee \left(c \wedge d \wedge \neg b\right)$$
(c∧(¬b))∨(a∧c∧(¬b))∨(a∧d∧(¬b))∨(c∧d∧(¬b))
FNC
[src]
Ya está reducido a FNC
$$\neg b \wedge \left(a \vee c\right) \wedge \left(c \vee d\right)$$
(¬b)∧(a∨c)∧(c∨d)
FNDP
[src]
$$\left(c \wedge \neg b\right) \vee \left(a \wedge d \wedge \neg b\right)$$
(c∧(¬b))∨(a∧d∧(¬b))