Sr Examen
Expresión ¬C⊕(A∨D)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Solución detallada
$$\neg c ⊕ \left(a \vee d\right) = \left(a \wedge c\right) \vee \left(c \wedge d\right) \vee \left(\neg a \wedge \neg c \wedge \neg d\right)$$
Simplificación
[src]
$$\left(a \wedge c\right) \vee \left(c \wedge d\right) \vee \left(\neg a \wedge \neg c \wedge \neg d\right)$$
(a∧c)∨(c∧d)∨((¬a)∧(¬c)∧(¬d))
Tabla de verdad
+---+---+---+--------+ | a | c | d | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FNC
[src]
$$\left(c \vee \neg a\right) \wedge \left(c \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg c\right) \wedge \left(a \vee c \vee \neg d\right) \wedge \left(a \vee d \vee \neg a\right) \wedge \left(a \vee d \vee \neg c\right) \wedge \left(a \vee d \vee \neg d\right) \wedge \left(c \vee d \vee \neg a\right) \wedge \left(c \vee d \vee \neg c\right) \wedge \left(c \vee d \vee \neg d\right)$$
(c∨(¬a))∧(c∨(¬c))∧(c∨(¬d))∧(a∨c∨(¬a))∧(a∨c∨(¬c))∧(a∨c∨(¬d))∧(a∨d∨(¬a))∧(a∨d∨(¬c))∧(a∨d∨(¬d))∧(c∨d∨(¬a))∧(c∨d∨(¬c))∧(c∨d∨(¬d))
FND
[src]
Ya está reducido a FND
$$\left(a \wedge c\right) \vee \left(c \wedge d\right) \vee \left(\neg a \wedge \neg c \wedge \neg d\right)$$
(a∧c)∨(c∧d)∨((¬a)∧(¬c)∧(¬d))
FNDP
[src]
$$\left(a \wedge c\right) \vee \left(c \wedge d\right) \vee \left(\neg a \wedge \neg c \wedge \neg d\right)$$
(a∧c)∨(c∧d)∨((¬a)∧(¬c)∧(¬d))
FNCD
[src]
$$\left(c \vee \neg a\right) \wedge \left(c \vee \neg d\right) \wedge \left(a \vee d \vee \neg c\right)$$
(c∨(¬a))∧(c∨(¬d))∧(a∨d∨(¬c))