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Lógica matemática/ (P∨Q)∧(¬P∨R)

Expresión (P∨Q)∧(¬P∨R)

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    Solución

    Ha introducido [src] 
    (p∨q)∧(r∨(¬p))
    $$\left(p \vee q\right) \wedge \left(r \vee \neg p\right)$$
    Solución detallada
    $$\left(p \vee q\right) \wedge \left(r \vee \neg p\right) = \left(p \wedge r\right) \vee \left(q \wedge \neg p\right)$$
    Simplificación [src]
    $$\left(p \wedge r\right) \vee \left(q \wedge \neg p\right)$$ 
    (p∧r)∨(q∧(¬p))
    Tabla de verdad 
    +---+---+---+--------+
| p | q | r | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    $$\left(p \vee q\right) \wedge \left(r \vee \neg p\right)$$ 
    (p∨q)∧(r∨(¬p))
    FNDP [src]
    $$\left(p \wedge r\right) \vee \left(q \wedge \neg p\right)$$ 
    (p∧r)∨(q∧(¬p))
    FND [src]
    Ya está reducido a FND
    $$\left(p \wedge r\right) \vee \left(q \wedge \neg p\right)$$ 
    (p∧r)∨(q∧(¬p))
    FNC [src]
    $$\left(p \vee q\right) \wedge \left(p \vee \neg p\right) \wedge \left(q \vee r\right) \wedge \left(r \vee \neg p\right)$$ 
    (p∨q)∧(q∨r)∧(p∨(¬p))∧(r∨(¬p))
    © Sr Examen