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Expresión (A∧~B)∨(B∧~C)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧(¬b))∨(b∧(¬c))
    $$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg c\right)$$
    Simplificación [src]
    $$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg c\right)$$
    (a∧(¬b))∨(b∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNC [src]
    $$\left(a \vee b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg b\right) \wedge \left(\neg b \vee \neg c\right)$$
    (a∨b)∧(a∨(¬c))∧(b∨(¬b))∧((¬b)∨(¬c))
    FNCD [src]
    $$\left(a \vee b\right) \wedge \left(\neg b \vee \neg c\right)$$
    (a∨b)∧((¬b)∨(¬c))
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg c\right)$$
    (a∧(¬b))∨(b∧(¬c))
    FNDP [src]
    $$\left(a \wedge \neg b\right) \vee \left(b \wedge \neg c\right)$$
    (a∧(¬b))∨(b∧(¬c))