Expresión !xy!z+xy+x!yz
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Solución
Solución detallada
$$\left(x \wedge y\right) \vee \left(x \wedge z \wedge \neg y\right) \vee \left(y \wedge \neg x \wedge \neg z\right) = \left(x \wedge z\right) \vee \left(y \wedge \neg z\right)$$
$$\left(x \wedge z\right) \vee \left(y \wedge \neg z\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(x \wedge z\right) \vee \left(y \wedge \neg z\right)$$
Ya está reducido a FND
$$\left(x \wedge z\right) \vee \left(y \wedge \neg z\right)$$
$$\left(x \vee \neg z\right) \wedge \left(y \vee z\right)$$
$$\left(x \vee y\right) \wedge \left(x \vee \neg z\right) \wedge \left(y \vee z\right) \wedge \left(z \vee \neg z\right)$$
(x∨y)∧(y∨z)∧(x∨(¬z))∧(z∨(¬z))