Sr Examen

Expresión (!(a&b)&cva&b&!cva&c)&(!avb)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (b∨(¬a))∧((a∧c)∨(a∧b∧(¬c))∨(c∧(¬(a∧b))))
    $$\left(b \vee \neg a\right) \wedge \left(\left(a \wedge c\right) \vee \left(c \wedge \neg \left(a \wedge b\right)\right) \vee \left(a \wedge b \wedge \neg c\right)\right)$$
    Solución detallada
    $$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
    $$c \wedge \neg \left(a \wedge b\right) = c \wedge \left(\neg a \vee \neg b\right)$$
    $$\left(a \wedge c\right) \vee \left(c \wedge \neg \left(a \wedge b\right)\right) \vee \left(a \wedge b \wedge \neg c\right) = c \vee \left(a \wedge b\right)$$
    $$\left(b \vee \neg a\right) \wedge \left(\left(a \wedge c\right) \vee \left(c \wedge \neg \left(a \wedge b\right)\right) \vee \left(a \wedge b \wedge \neg c\right)\right) = \left(a \wedge b\right) \vee \left(c \wedge \neg a\right)$$
    Simplificación [src]
    $$\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)$$
    (a∧b)∨(c∧(¬a))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    $$\left(a \vee c\right) \wedge \left(a \vee \neg a\right) \wedge \left(b \vee c\right) \wedge \left(b \vee \neg a\right)$$
    (a∨c)∧(b∨c)∧(a∨(¬a))∧(b∨(¬a))
    FNDP [src]
    $$\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)$$
    (a∧b)∨(c∧(¬a))
    FNCD [src]
    $$\left(a \vee c\right) \wedge \left(b \vee \neg a\right)$$
    (a∨c)∧(b∨(¬a))
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)$$
    (a∧b)∨(c∧(¬a))