Sr Examen
Expresión ((pv~r)^~r)→(p^q)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
((¬r)∧(p∨(¬r)))⇒(p∧q)
$$\left(\neg r \wedge \left(p \vee \neg r\right)\right) \Rightarrow \left(p \wedge q\right)$$
Solución detallada
$$\neg r \wedge \left(p \vee \neg r\right) = \neg r$$
$$\left(\neg r \wedge \left(p \vee \neg r\right)\right) \Rightarrow \left(p \wedge q\right) = r \vee \left(p \wedge q\right)$$
$$\left(\neg r \wedge \left(p \vee \neg r\right)\right) \Rightarrow \left(p \wedge q\right) = r \vee \left(p \wedge q\right)$$
Tabla de verdad
+---+---+---+--------+ | p | q | r | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+