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Expresión (¬bv(¬c&¬a))v(av(b&c))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨(¬b)∨(b∧c)∨((¬a)∧(¬c))
    $$a \vee \left(b \wedge c\right) \vee \left(\neg a \wedge \neg c\right) \vee \neg b$$
    Solución detallada
    $$a \vee \left(b \wedge c\right) \vee \left(\neg a \wedge \neg c\right) \vee \neg b = 1$$
    Simplificación [src]
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    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FNDP [src]
    1
    1
    FNCD [src]
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1