Expresión A(BC+AC)+BC
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge c\right) \vee \left(b \wedge c\right) = c \wedge \left(a \vee b\right)$$
$$a \wedge \left(\left(a \wedge c\right) \vee \left(b \wedge c\right)\right) = a \wedge c$$
$$\left(a \wedge \left(\left(a \wedge c\right) \vee \left(b \wedge c\right)\right)\right) \vee \left(b \wedge c\right) = c \wedge \left(a \vee b\right)$$
$$c \wedge \left(a \vee b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$c \wedge \left(a \vee b\right)$$
$$\left(a \wedge c\right) \vee \left(b \wedge c\right)$$
$$\left(a \wedge c\right) \vee \left(b \wedge c\right)$$
Ya está reducido a FNC
$$c \wedge \left(a \vee b\right)$$