Expresión ¬c¬a∨¬cb
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(b∧¬c)∨(¬a∧¬c)=¬c∧(b∨¬a)
¬c∧(b∨¬a)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
Ya está reducido a FNC
¬c∧(b∨¬a)
(b∧¬c)∨(¬a∧¬c)
¬c∧(b∨¬a)
(b∧¬c)∨(¬a∧¬c)