Sr Examen

Expresión (~w+~x+~y+~z)*(~w+~x+~y+z)*(~w+~x+y+~z)*(~w+~x+y+z)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (y∨z∨(¬w)∨(¬x))∧(y∨(¬w)∨(¬x)∨(¬z))∧(z∨(¬w)∨(¬x)∨(¬y))∧((¬w)∨(¬x)∨(¬y)∨(¬z))
    $$\left(y \vee z \vee \neg w \vee \neg x\right) \wedge \left(y \vee \neg w \vee \neg x \vee \neg z\right) \wedge \left(z \vee \neg w \vee \neg x \vee \neg y\right) \wedge \left(\neg w \vee \neg x \vee \neg y \vee \neg z\right)$$
    Solución detallada
    $$\left(y \vee z \vee \neg w \vee \neg x\right) \wedge \left(y \vee \neg w \vee \neg x \vee \neg z\right) \wedge \left(z \vee \neg w \vee \neg x \vee \neg y\right) \wedge \left(\neg w \vee \neg x \vee \neg y \vee \neg z\right) = \neg w \vee \neg x$$
    Simplificación [src]
    $$\neg w \vee \neg x$$
    (¬w)∨(¬x)
    Tabla de verdad
    +---+---+---+---+--------+
    | w | x | y | z | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    FNDP [src]
    $$\neg w \vee \neg x$$
    (¬w)∨(¬x)
    FNC [src]
    Ya está reducido a FNC
    $$\neg w \vee \neg x$$
    (¬w)∨(¬x)
    FND [src]
    Ya está reducido a FND
    $$\neg w \vee \neg x$$
    (¬w)∨(¬x)
    FNCD [src]
    $$\neg w \vee \neg x$$
    (¬w)∨(¬x)