Sr Examen

Expresión (P→Q)∧R

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    r∧(p⇒q)
    $$r \wedge \left(p \Rightarrow q\right)$$
    Solución detallada
    $$p \Rightarrow q = q \vee \neg p$$
    $$r \wedge \left(p \Rightarrow q\right) = r \wedge \left(q \vee \neg p\right)$$
    Simplificación [src]
    $$r \wedge \left(q \vee \neg p\right)$$
    r∧(q∨(¬p))
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$r \wedge \left(q \vee \neg p\right)$$
    r∧(q∨(¬p))
    FND [src]
    $$\left(q \wedge r\right) \vee \left(r \wedge \neg p\right)$$
    (q∧r)∨(r∧(¬p))
    FNC [src]
    Ya está reducido a FNC
    $$r \wedge \left(q \vee \neg p\right)$$
    r∧(q∨(¬p))
    FNDP [src]
    $$\left(q \wedge r\right) \vee \left(r \wedge \neg p\right)$$
    (q∧r)∨(r∧(¬p))