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Lógica matemática/ (BD)+B(!C)

Expresión (BD)+B(!C)

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    Solución

    Ha introducido [src] 
    (b∧d)∨(b∧(¬c))
    $$\left(b \wedge d\right) \vee \left(b \wedge \neg c\right)$$
    Solución detallada
    $$\left(b \wedge d\right) \vee \left(b \wedge \neg c\right) = b \wedge \left(d \vee \neg c\right)$$
    Simplificación [src]
    $$b \wedge \left(d \vee \neg c\right)$$ 
    b∧(d∨(¬c))
    Tabla de verdad 
    +---+---+---+--------+
| b | c | d | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$b \wedge \left(d \vee \neg c\right)$$ 
    b∧(d∨(¬c))
    FNCD [src]
    $$b \wedge \left(d \vee \neg c\right)$$ 
    b∧(d∨(¬c))
    FNDP [src]
    $$\left(b \wedge d\right) \vee \left(b \wedge \neg c\right)$$ 
    (b∧d)∨(b∧(¬c))
    FND [src]
    $$\left(b \wedge d\right) \vee \left(b \wedge \neg c\right)$$ 
    (b∧d)∨(b∧(¬c))
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