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Lógica matemática/ сv(a&b&c)&¬b

Expresión сv(a&b&c)&¬b

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    Solución

    Ha introducido [src] 
    c∨(a∧b∧c∧(¬b))
    $$c \vee \left(a \wedge b \wedge c \wedge \neg b\right)$$
    Solución detallada
    $$a \wedge b \wedge c \wedge \neg b = \text{False}$$
    $$c \vee \left(a \wedge b \wedge c \wedge \neg b\right) = c$$
    Simplificación [src]
    $$c$$ 
    c
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$c$$ 
    c
    FNC [src]
    Ya está reducido a FNC
    $$c$$ 
    c
    FNCD [src]
    $$c$$ 
    c
    FND [src]
    Ya está reducido a FND
    $$c$$ 
    c
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