Expresión (p∧(q∨¬r))∨(¬r∧q)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(p \wedge \left(q \vee \neg r\right)\right) \vee \left(q \wedge \neg r\right) = \left(p \wedge q\right) \vee \left(p \wedge \neg r\right) \vee \left(q \wedge \neg r\right)$$
$$\left(p \wedge q\right) \vee \left(p \wedge \neg r\right) \vee \left(q \wedge \neg r\right)$$
Tabla de verdad
+---+---+---+--------+
| p | q | r | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(p \vee q\right) \wedge \left(p \vee \neg r\right) \wedge \left(q \vee \neg r\right)$$
$$\left(p \vee q\right) \wedge \left(p \vee \neg r\right) \wedge \left(q \vee \neg r\right) \wedge \left(p \vee q \vee \neg r\right)$$
(p∨q)∧(p∨(¬r))∧(q∨(¬r))∧(p∨q∨(¬r))
Ya está reducido a FND
$$\left(p \wedge q\right) \vee \left(p \wedge \neg r\right) \vee \left(q \wedge \neg r\right)$$
$$\left(p \wedge q\right) \vee \left(p \wedge \neg r\right) \vee \left(q \wedge \neg r\right)$$