Sr Examen
Expresión ¬((¬x)∨(¬y)∨(x∧z))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
¬((¬x)∨(¬y)∨(x∧z))
$$\neg \left(\left(x \wedge z\right) \vee \neg x \vee \neg y\right)$$
Solución detallada
$$\left(x \wedge z\right) \vee \neg x \vee \neg y = z \vee \neg x \vee \neg y$$
$$\neg \left(\left(x \wedge z\right) \vee \neg x \vee \neg y\right) = x \wedge y \wedge \neg z$$
$$\neg \left(\left(x \wedge z\right) \vee \neg x \vee \neg y\right) = x \wedge y \wedge \neg z$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+