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Lógica matemática/ (P∧Q)∨(P∧R)∨(Q∧R)

Expresión (P∧Q)∨(P∧R)∨(Q∧R)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (p∧q)∨(p∧r)∨(q∧r)
    $$\left(p \wedge q\right) \vee \left(p \wedge r\right) \vee \left(q \wedge r\right)$$
    Simplificación [src]
    $$\left(p \wedge q\right) \vee \left(p \wedge r\right) \vee \left(q \wedge r\right)$$ 
    (p∧q)∨(p∧r)∨(q∧r)
    Tabla de verdad 
    +---+---+---+--------+
| p | q | r | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    $$\left(p \vee q\right) \wedge \left(p \vee r\right) \wedge \left(q \vee r\right) \wedge \left(p \vee q \vee r\right)$$ 
    (p∨q)∧(p∨r)∧(q∨r)∧(p∨q∨r)
    FNDP [src]
    $$\left(p \wedge q\right) \vee \left(p \wedge r\right) \vee \left(q \wedge r\right)$$ 
    (p∧q)∨(p∧r)∨(q∧r)
    FND [src]
    Ya está reducido a FND
    $$\left(p \wedge q\right) \vee \left(p \wedge r\right) \vee \left(q \wedge r\right)$$ 
    (p∧q)∨(p∧r)∨(q∧r)
    FNCD [src]
    $$\left(p \vee q\right) \wedge \left(p \vee r\right) \wedge \left(q \vee r\right)$$ 
    (p∨q)∧(p∨r)∧(q∨r)
    © Sr Examen