Expresión ¬(¬(AB)C∨¬(A∨¬B)¬C)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$c \wedge \neg \left(a \wedge b\right) = c \wedge \left(\neg a \vee \neg b\right)$$
$$\neg \left(a \vee \neg b\right) = b \wedge \neg a$$
$$\neg c \wedge \neg \left(a \vee \neg b\right) = b \wedge \neg a \wedge \neg c$$
$$\left(c \wedge \neg \left(a \wedge b\right)\right) \vee \left(\neg c \wedge \neg \left(a \vee \neg b\right)\right) = \left(b \wedge \neg a\right) \vee \left(c \wedge \neg b\right)$$
$$\neg \left(\left(c \wedge \neg \left(a \wedge b\right)\right) \vee \left(\neg c \wedge \neg \left(a \vee \neg b\right)\right)\right) = \left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right) \wedge \left(b \vee \neg b\right) \wedge \left(b \vee \neg c\right)$$
(a∨(¬b))∧(a∨(¬c))∧(b∨(¬b))∧(b∨(¬c))
Ya está reducido a FND
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\left(a \vee \neg b\right) \wedge \left(b \vee \neg c\right)$$
$$\left(a \wedge b\right) \vee \left(\neg b \wedge \neg c\right)$$